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improper integrals, convergent or divergent? follow-up  TOPIC_SOLVED

In this thread , a poster said: To be convergent, an integral must have a finite value. If the value is not finite, then the integral, by definition, does not converge. What about cases like \lim_{a \rightarrow \infty} \int_0^a \sin x dx ? This doesn't go to infinity but still it doesn't converge.
by TomasRiker
on Mon Feb 04, 2013 1:44 pm
 
Forum: Calculus
Topic: improper integrals, convergent or divergent? follow-up
Replies: 1
Views: 1851

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