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Re: Question on deriving the quadratic formula  TOPIC_SOLVED

everything got divided through by "a" (step 4), which leaves the whole equation essentially unchanged. You just didn't notice, that's all. After step 5, which is not shown in your post, multiply the term "-c/a" by "4a/4a", which will give you "-4ac/4a 2 " Add ...
by strumbore
on Fri Jan 11, 2013 12:08 am
 
Forum: Intermediate Algebra
Topic: Question on deriving the quadratic formula
Replies: 5
Views: 2002

Re: I need help developing an equation  TOPIC_SOLVED

This is called an "arithmetic series". Each term in an arithmetic series ALWAYS has a difference of "d" between each term. Subtract any term in this sequence by the one that preceded it and the answer is always d=(I'll let you figure this one out). If you want to calculate the ac...
by strumbore
on Fri Jan 11, 2013 12:36 am
 
Forum: Advanced Algebra ("pre-calculus")
Topic: I need help developing an equation
Replies: 4
Views: 2621

Re: Expand Expression  TOPIC_SOLVED

Expanding log3[3SQRT(x/81)]

here are 5 BIG HINTS:

1) Product Property of Logarithms
2) A root is an exponent (find out what SQRT means!)
3) Power Property of Logarithms
4) Quotient Property of Logarithms

5) logaa = 1

Now just do it!

...

ok, answer is (1/2)log3x - 2
by strumbore
on Fri Jan 11, 2013 12:51 am
 
Forum: Advanced Algebra ("pre-calculus")
Topic: Expand Expression
Replies: 2
Views: 1430

Re: Linear equation deduction enigma  TOPIC_SOLVED

No one's gonna look at this, and I don't know if this helps, but from a Production standpoint in EconA: Skilled Labor produces y more effectively Unskilled Labor produces x more effectively EconA producing soly x or y is double the output of that of that in EconB. Graph all 3 lines on the same plane...
by strumbore
on Fri Jan 11, 2013 2:08 am
 
Forum: Advanced Algebra ("pre-calculus")
Topic: Linear equation deduction enigma
Replies: 2
Views: 3392

Re: I need help developing an equation  TOPIC_SOLVED

I guess OP isn't coming back, so the answers are

an= 5(3n-1)

and

Sn=(10/2)[(10)+(145)]= $775.
by strumbore
on Sat Jan 12, 2013 9:39 am
 
Forum: Advanced Algebra ("pre-calculus")
Topic: I need help developing an equation
Replies: 4
Views: 2621

Re: Factoring trinomials: 2a^2 + 3a + 1  TOPIC_SOLVED

Those are REALLY good suggestions, the last one is actually the fastest way to solve the problem. But remember that if you ever get stuck, there is a guaranteed solution to any quadratic equation using the Quadratic Formula (and if there isn't, it means the equation is unsolvable, or at least has no...
by strumbore
on Sat Jan 12, 2013 9:54 am
 
Forum: Intermediate Algebra
Topic: Factoring trinomials: 2a^2 + 3a + 1
Replies: 3
Views: 4871

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