Solving for just b , do these first: *Add +bx to both sides, *Multiply both sides by (1/x) That will give you b as a function of x , which seems to be a variable, possibly of two complex numbers. If these values for x are to be in the form, a 1 +a 2 i, then you want a 2 =0, since you specified wanti...

- on Sat Dec 29, 2012 3:18 am
- Forum: Intermediate Algebra
- Topic: x^2-bx+18=0
- Replies:
**3** - Views:
**1505**

More efficient to multiply numerator and denominator by the lowest common denominator, .

The simplification process is a little easier.

The simplification process is a little easier.

- on Mon Dec 31, 2012 6:06 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Difficult problem! please help
- Replies:
**3** - Views:
**1671**

You must measure the summand vectors, but you can then measure the resulting vector to check your work.

- on Thu Jan 03, 2013 2:00 am
- Forum: Trigonometry
- Topic: Trigonometry - Graphing vectors.
- Replies:
**5** - Views:
**2467**

spellbinder2050 asks this: Is graphing an accurate depiction of the new magnitude important? If so, I need an explanation of how it is done. My book does not explain how accurate my graph has to be. Yes, graphing a vector, including operations on vectors, is important; at least for the learning proc...

- on Thu Jan 03, 2013 2:09 am
- Forum: Trigonometry
- Topic: Trigonometry - Graphing vectors.
- Replies:
**5** - Views:
**2467**

Could you express the formula for the Chain Rule?

Starting specifically with f(x)=3sin^3(x^2), or 3sin^{3}(x^{2}), you have h(x)=x^{2}, and g(x)=3sin^{3}(x)

You have the composition, g(h(x)). You are interested in the derivative of g(h(x)) with respect to x.

Starting specifically with f(x)=3sin^3(x^2), or 3sin

You have the composition, g(h(x)). You are interested in the derivative of g(h(x)) with respect to x.

- on Thu Jan 03, 2013 2:18 am
- Forum: Calculus
- Topic: Derivatives ~Chain rule
- Replies:
**1** - Views:
**1943**

It's a function y, of the independent variable, x. The function is in factored form. If you have that y=0,

then the resulting quadratic equation is 0=(2x+5)(3x-7), obviously still in factored form. This may be overly picky.

then the resulting quadratic equation is 0=(2x+5)(3x-7), obviously still in factored form. This may be overly picky.

- on Fri Jan 04, 2013 4:44 am
- Forum: Intermediate Algebra
- Topic: Is y=(2x+5)(3x-7) considered factored form of a quadratic?
- Replies:
**1** - Views:
**1001**

A somewhat less refined but logical approach is to fill this with possibilities to test:

...but will anything work? Your only choices to make product of 1 are 1 X 1.

- Code: Select all
`(2a + ___)(a + ___)`

...but will anything work? Your only choices to make product of 1 are 1 X 1.

- on Fri Jan 04, 2013 4:54 am
- Forum: Intermediate Algebra
- Topic: Factoring trinomials: 2a^2 + 3a + 1
- Replies:
**3** - Views:
**3669**

A good set of lessons for combinations and permutations on purplemath site would be great. One of my old Intermediate Algebra books has a couple of sections on these and although good, is not very deep. An old College Algebra book or two here also has some sections on combinations and permutations, ...

- on Fri Jan 04, 2013 5:59 am
- Forum: Forum Rules & Guides
- Topic: Make some lessons on combinations and permutations
- Replies:
**0** - Views:
**4877**

You can solve for y, but you can't find a value for y. Your equation has two variables, and neither is given a value. Can you solve for y? The WAY to solve it,....Three steps. Focus on "y". The given equation: 2x + [24-2 (y)] = 20 What is the first thing you see that is done to y? What is ...

- on Sat Jan 05, 2013 9:56 pm
- Forum: Intermediate Algebra
- Topic: Please find the value Y in this given equation?
- Replies:
**2** - Views:
**1456**

"Velocity relative to the air," is not too comfortable wording. Maybe this is just difficult to interpret. The way I can make sense of the description and question is, the jet is 500 m/h pointing downward (south), the wind vector80 m/h, is 135 degrees to the left relative to the jet's dire...

- on Sun Jan 06, 2013 9:23 pm
- Forum: Trigonometry
- Topic: vectors: finding the actual speed and direction of aircraft
- Replies:
**3** - Views:
**1966**