- Tue Feb 17, 2015 1:10 am
- Forum: Discrete Math
- Topic: Express how many ways you can select a representative
- Replies:
**1** - Views:
**65**

Assume that a school has these three teams: Chess team with 10 members, Checkers team with 15 members, and College bowl team with 20 members. In how many ways can we select rep of the school if there should be: 1. exactly 1 representative from each team. Do the multiplication formula they showed yo...

- Wed Feb 11, 2015 3:36 am
- Forum: Beginning Algebra
- Topic: Linear Equations: Slope Problem.
- Replies:
**3** - Views:
**124**

I need help with this problem. I need to see if this problem will be an independent, inconsistent, consistent or dependent. These terms are for SYSTEMS of equations. The linear equation is: -X + 4y=4 X - 4y= -4 This is a SYSTEM of equations, not just one linear equation, as written. But then the x'...

- Wed Feb 11, 2015 3:33 am
- Forum: Beginning Algebra
- Topic: 2 Mechanics.
- Replies:
**8** - Views:
**118**

There are 2 mechanics by which the 1st one works for 75 an hr and then the second mech works for 55 an hour. Altogether they work 15 hours for an amount of 1025. What are the hours of both mechanics? You can learn how to set up this sort of thing here . First you translate the English into math: fi...

- Tue Feb 10, 2015 1:14 pm
- Forum: Intermediate Algebra
- Topic: Selection the solution and graph the inequality
- Replies:
**4** - Views:
**172**

It would be the second one: \dfrac{3}{8x}\, -\, \dfrac{1}{4x}\, <\, \dfrac{4}{5}\,\left(\dfrac{5}{32x}\, -\, 1\right) Thanks. Now what did you do with the LCM that didn't work? This is an inequality so you can't times through by a variable so you moved everything over to one side: 0\, <\, \...

- Tue Feb 10, 2015 1:10 pm
- Forum: Calculus
- Topic: finding volume of solids using cylindrical shells method
- Replies:
**2** - Views:
**123**

The question I have is about finding volume of solids using cylindrical shells method: The solid formed by rotating the region in the first quadrant bounded by y=0 and y=-x^3+x about the y=2 axis. To get the endpoints, do a graph . The factorization y = x(1-x)(1+x) says the zeroes are x=-1,0,+1. In...

- Wed Feb 04, 2015 12:35 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Simplifying an Exponential Function (Calc 2)
- Replies:
**2** - Views:
**183**

Does anyone have any hints/solution to the following two problems? Your subject line says "calc 2" which is integration, but this looks like algebra? Plus you say "simplifying" and "functions", but there aren't functions (no function names) and three look like you're s...

- Sun Feb 01, 2015 2:37 pm
- Forum: Intermediate Algebra
- Topic: Formulas and Functions problem
- Replies:
**3** - Views:
**195**

Solve the equation. Round the answer to three decimal places. 1/8 - 5/7(x - 5/22) = 6x/25 + 1/13 How you did this means like this: \dfrac{1}{8}\, -\, \dfrac{5}{7\, \left(x\, -\, \dfrac{5}{22}\right)}\, =\, \dfrac{6x}{25}\, +\, \dfrac{1}{13} I think you meant 1/8 - (5/7)(x - 5/22) so like th...

- Wed Jan 21, 2015 12:10 pm
- Forum: Intermediate Algebra
- Topic: (2a+b+1)x=(a-b-4) & Infinite Number of Solutions
- Replies:
**5** - Views:
**450**

The whole problem is this: Determine the values of a and b, knowing that the equation has infinite answers. (2a+b+1)x=(a-b-4) I took as referense this example problem that my teacher give me cx - 2x + d - 2= -3x - d cx - 2x + d +3x - 2= - d cx - 2x + d +3x - 2= - d cx + x +d - 2 = -d cx + x +d = -d...

- Tue Jan 20, 2015 4:04 pm
- Forum: Intermediate Algebra
- Topic: (2a+b+1)x=(a-b-4) & Infinite Number of Solutions
- Replies:
**5** - Views:
**450**

I have to find the values for a and b , but it needs to have a infinite number of solutions (2a+b+1)x=(a-b-4) 2ax+bx+x=a-b-4 2ax-a=-b-4-bx-x a(2x-1)=-b-4-bx-x 2x-1=0 I did this, just guessing.... 2x=1 x=1/2 2ax+bx+x=a-b-4 bx+b=a-4-2ax-x b(x+1)=a-4-2ax-x x+1=0 x=-1 (2a+b+1)x=...

- Tue Jan 20, 2015 3:58 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: fractional or negative exponents
- Replies:
**1** - Views:
**186**

I'm struggling to understand the process for simplifying algebraic expressions that contain fractional or negative exponents. They've got lessons here for negative powers and fractional powers. For example: [(x^2 + 3)^(-2/3)] + [(x^2 + 3)^(-5/3)] Do like the lessons show. 1st, 5/3 = 1 + 1/2/3 so yo...