I am having trouble solving polar equations.

1. r= 1-sin theta

2. r=3+2sin theta

how would i go about solving these so that i would be able to graph them ?

- Fri Dec 14, 2012 11:35 pm
- Forum: Trigonometry
- Topic: polar equations
- Replies:
**1** - Views:
**3619**

I am having trouble solving polar equations.

1. r= 1-sin theta

2. r=3+2sin theta

how would i go about solving these so that i would be able to graph them ?

1. r= 1-sin theta

2. r=3+2sin theta

how would i go about solving these so that i would be able to graph them ?

- Tue Nov 27, 2012 12:36 am
- Forum: Trigonometry
- Topic: graphing with tan: y = tan(pi*x) + 2
- Replies:
**5** - Views:
**3503**

Yes I read the link completely the problem I am having is that it doesn't tell me what the pi does on the inside to the variables. I understand everything about graphing it and all i just don't know what the pi next to x does to each value

- Mon Nov 26, 2012 10:11 pm
- Forum: Trigonometry
- Topic: graphing with tan: y = tan(pi*x) + 2
- Replies:
**5** - Views:
**3503**

sorry i guess i did make that a little complicated im supposed to graph y=tan(pi*x)+2 i set up my table like this for the graph x,y untraslated = -3pi/4,1 -pi/2,undefined -pi/4 0,-1 pi/4,undefined pi/2,1 3pi/4,-1 i understand you just add 2 to the y coordinate but i do not know how i would translate...

- Mon Nov 26, 2012 5:13 pm
- Forum: Trigonometry
- Topic: graphing with tan: y = tan(pi*x) + 2
- Replies:
**5** - Views:
**3503**

Now i know this is probably a basic question so please forgive me. i have a problem y = tan(pi*x) + 2 iv established my points as x = -3pi/2 -pi/2 -pi/4 0 pi/4 pi/2 and 3pi/4 the problem is I don't quite grasp what would happen to my x points when i multiply them by pi an explanation would be great ...