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expanding logs: solve [3e^{-5x}=132] algebraically  TOPIC_SOLVED

Solve the equation algebraically. Approximate your result to three decimal places.

[3e^{-5x}=132]
by jordanriner26
on Sun Oct 07, 2012 5:57 pm
 
Forum: Advanced Algebra ("pre-calculus")
Topic: expanding logs: solve [3e^{-5x}=132] algebraically
Replies: 1
Views: 1493

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