- Sun Sep 16, 2012 9:10 pm
- Forum: Beginning Algebra
- Topic: Fractional Algebriac Equation help!!
- Replies:
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**1824**

Hi, when I try to solve the equation below, I come up with 36, as seen below. I multiply each term by two in order to get rid of the fractions. The correct answer is 72. What am I doing wrong? a+b+c+d = 180 b = a/2 c=b/2 d=3c a + a/2 + (a/2)/2 + 3[(a/2)/2] = 180 which becomes... a + a/2 + (a/2 * 1/2...