- Tue Jan 27, 2015 10:43 pm
- Forum: Trigonometry
- Topic: Angle of an Isosceles triangle for any opposite side length.
- Replies:
**2** - Views:
**196**

ABC is a triangle. Opposite the vertices A, B, and C are the sides a, b, and c, respectively. (thanks for the syntax help). This is an Isosceles triangle since a and b are the same length. What formula can I use to determine the angle C for a given c. I am trying to write a function that will retur...

- Fri Jan 16, 2015 3:34 am
- Forum: Intermediate Algebra
- Topic: reverse formula
- Replies:
**4** - Views:
**414**

Dear Forum members , Can someone help me to turn this formula so I can calculate ta . thank you in advance, Mon. P = P50 [ (ti - tr) / ln( (ti - ta) / (tr - ta) ) 1 / 49.32 ]n (1) ta = ........ I don't know what you mean by "turning" the "formula" to calculate "ta". Ma...

- Thu Jan 15, 2015 1:18 pm
- Forum: Intermediate Algebra
- Topic: Help to create an Algebraic equation
- Replies:
**3** - Views:
**309**

A couple living together have a combined bill payment of $1600. Jane makes a wage of $2900 a month and John makes a wage of $2000 a month. To make it fair John should pay a bit less percentage of his wage (being the lesser income maker) towards the bill so they have an equal amount percentage of in...

- Sun Jan 11, 2015 4:30 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Difficult question
- Replies:
**7** - Views:
**547**

the question is how long does it take to get to 180 feet. I tried to come up with an answer using the equation you provided but am having a trouble breaking it down. I came up with h(t) = 16t^2-144t+180 and I cant get it simplified enough to solve for t. There's nothing to solve the way you're doin...

- Sun Jan 11, 2015 4:27 am
- Forum: Trigonometry
- Topic: trig identities...again
- Replies:
**1** - Views:
**239**

I'm stuck on one of the last questions in my textbook and would appreciate any help... Use the sum or product identities to simplify the following [sin(@)+2sin(2@)+sin(3@)] / [cos(@)+2cos(2@)+3cos(3@)] I was going to ask if theres supposed to be a 3 in front of the sin(3@) but Wolfram Alpha can't s...

- Tue Dec 16, 2014 2:41 pm
- Forum: Geometry
- Topic: Find the area of polygon
- Replies:
**3** - Views:
**560**

I have read in easycalculation site that using pick's theorem, area of the polygon can be calculated by joining the lattice points...Need more explanation on this. The formula looks pretty easy: count the points "i" inside, count the points "b" on the edge ("boundary")...

- Tue Nov 18, 2014 12:13 pm
- Forum: Intermediate Algebra
- Topic: Relationship between a square and a parabola?
- Replies:
**3** - Views:
**713**

In other words, the "square" in "completing the square" has nothing to do with the four-cornered geometrical shape. It has to do with moving something around until you get it to be something that is the square (to the power 2) of something else. The shape of the graph is always g...

- Wed Nov 12, 2014 12:51 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Sequences
- Replies:
**2** - Views:
**615**

"Find first 4 terms" c_0=-2, c_j=\frac{c_j_-_1}{(j+1)(j+2) , j\geq1 So, do you start at -2 for j? And then go -1, 0, 1? The -2 is the value for the first term. The j is the counter. They're totally separate things. c_0 could be anything: 3, -100, 87, etc. It's just what yo...

- Wed Nov 12, 2014 12:49 pm
- Forum: Intermediate Algebra
- Topic: Simplify Negative square roots.
- Replies:
**1** - Views:
**441**

How do you simplify this: (-15 ± sqrt(-675)) / 50. They show step-by-step examples here . Start by factoring everything: 675 = 25*9*3, 15 = 5*3, 50 = 5*5*2. (You do squares for the 675 b/c you're inside a radical so you need squares to take out.) Then sqrt(-675)=sqrt(-1)sqrt(25)sqrt(9)sqrt(3). Take...

- Mon Oct 27, 2014 11:10 am
- Forum: Intermediate Algebra
- Topic: Many problems
- Replies:
**1** - Views:
**472**

1. Solve for x. Show all work. 3x^2-1x/2=-3/4 Is the LHS 3x^2 - (1/2)x or is it (3x^2 - x)/2? Either way, move the -3/4 to the LHS, times thru by 4 to get rid of the denom's, and then solve. Do you know the quadratic formula ? 2. If mn=5 and m-3n=8, what is m^2n-3mn^2. (p.s. the m^2n is like m^2*n)...