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by buddy
Sun Jul 12, 2015 4:38 pm
Forum: Trigonometry
Topic: Determining exact values for "Special trigonometric expressions"
Replies: 1
Views: 40

Re: Determining exact values for "Special trigonometric expressions"

Mainstrain wrote:2cos 45* x sin45*

i got this far, 2 square root3/2 x square root2/2 but am not sure what the next step is?

Multiply and simplify like you did back in algebra.
by buddy
Sun Jul 12, 2015 4:37 pm
Forum: Trigonometry
Topic: Reciprocal trigonometric ratios
Replies: 5
Views: 48

Re: Reciprocal trigonometric ratios

ok i did 1/tan(3.2404) and got 17 which is the correct answer, however when i went to the second problem i did 1/sin(1.2711)and got 45 You have a tan -1 key on your calculator but not a cot -1 . To find the inverse of the cotangent you have to convert to tangent form. Why are you converting the sin...
by buddy
Sun Jul 12, 2015 4:35 pm
Forum: Intermediate Algebra
Topic: Urgent problem, (simple?) linear programming,
Replies: 4
Views: 127

Re: Urgent problem, (simple?) linear programming,

What have you done so far?
by buddy
Fri Jul 10, 2015 12:35 pm
Forum: Advanced Algebra ("pre-calculus")
Topic: Geometric Sequences help
Replies: 2
Views: 137

Re: Geometric Sequences help

I feel like I'm spending an unnecessary amount of time guessing and checking for the common ratio. There isn't any guessing for common ratios. Just do the division and see if the answers match. Particularly when the majority of the numbers in the sequence are fractions. For example 27/64, 9/16, 3/4...
by buddy
Wed Jun 24, 2015 9:36 pm
Forum: Geometry
Topic: Need help with a sphere
Replies: 1
Views: 209

Re: Need help with a sphere

I have created a circle with points; this wasn't that hard. Now, I want to create a sphere using points. I'm not really sure what you're doing, but maybe spherical coordinated might help ( here ). You know the center and radius from the circle. Can you plug these into spherical coordinates to get t...
by buddy
Wed Jun 10, 2015 12:37 am
Forum: Advanced Algebra ("pre-calculus")
Topic: How to write an equation for an ellipse using height and width
Replies: 4
Views: 224

Re: How to write an equation for an ellipse using height and width

If you look at the second problem and answer then I would think that a = 1/3 and b=1/4 and my answer would be the reverse of the answer given You're actually right and the answer they gave you is wrong. You can check by graphing. Look at the graph of their equation: https://www.wolframalpha.com/inp...
by buddy
Mon Jun 08, 2015 4:27 pm
Forum: Beginning Algebra
Topic: Can't get fraction out of an equation
Replies: 2
Views: 193

Re: Can't get fraction out of an equation

At the link is this: Find equation of line. Write in f(x) Through (-5, -7); paralells [sic] 6x + 5y = 11 a) find slope 6x + 5y = 11 -6x . . . . . -6x 5y = 11 - 6x y = (11 - 6x)/5 y = 11/5 - (6/5)x b) y - y1 = m(x - x1) y - -7 = -(6/5)(x - -5) y + 7 = -(6/5)(x + 5) 5(y + 7) = 5*(-6/5)(x + 5) 5y + 35 ...
by buddy
Mon Jun 08, 2015 4:17 pm
Forum: Advanced Algebra ("pre-calculus")
Topic: How to write an equation for an ellipse using height and width
Replies: 4
Views: 224

Re: How to write an equation for an ellipse using height and width

Yes (if you're saying that your a^2 is bigger than your b^2). It's like they show here.
by buddy
Mon Jun 08, 2015 4:15 pm
Forum: Advanced Algebra ("pre-calculus")
Topic: How to find the center and radius of a circle with a large term
Replies: 3
Views: 206

Re: How to find the center and radius of a circle with a large term

mathpatient wrote:How can I find the center and radius of a circle given this equation:

x^2 + 4x + y^2 + 4y + (71/4)

This isn't an equation b/c there isn't an "=" in it. W/o that, you can't get the center or radius.
by buddy
Wed Jun 03, 2015 9:54 pm
Forum: Intermediate Algebra
Topic: Rational Expression Multiplication
Replies: 1
Views: 158

Re: Rational Expression Multiplication

I have worked and reworked the multiplication below, but can't get the correct answer. What did you do? What did you get? \left(\dfrac{ab-a+3b-3}{ab+a+4b-4}\right)\times \left(\dfrac{ab+2a-4b-8}{ab+2a+3b-6}\right) Do factoring in pairs. They show how here . ab - a + 3b - 3 = (ab - a...

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