## Search found 5 matches

Thu Aug 23, 2012 3:48 pm
Topic: Solving Rational Equations (Imaginary Answer?)
Replies: 4
Views: 4155

### Re: Solving Rational Equations (Imaginary Answer?)

Oh yeah, I didn't see the (x+2) that would cancel on both sides...thanks for the help!
Mon Aug 20, 2012 5:53 pm
Topic: Solving Rational Equations (Imaginary Answer?)
Replies: 4
Views: 4155

### Re: Solving Rational Equations (Imaginary Answer?)

Ok these were my steps... (im going to explain in words instead of pictures because it took me forever to post that last message) 1. factored the 4-x^2 into -(x+2)(x-2). 2. then i multiplied top and bottom of x/(x-2) by -(x+2) so now it also has the -(x+2)(x-2) denominator. 3. then i combined the fr...
Sun Aug 19, 2012 4:36 pm
Topic: Solving Rational Equations (Imaginary Answer?)
Replies: 4
Views: 4155

### Solving Rational Equations (Imaginary Answer?)

Problem: \frac{x}{x\, -\, 2}\, +\, \frac{2x}{4\, -\, x^2}\, =\, \frac{5}{x\, +\, 2} I can usually solve these kinds of problems pretty easily, but I got stuck with this one and when I checked the answer it was imaginary... I made a common denominator of -(x-2)(x+2) on the left side and then combined...
Sun Aug 19, 2012 3:48 pm
Forum: Trigonometry
Topic: Solving Trig Inequalities...Need help.
Replies: 2
Views: 7492

### Re: Solving Trig Inequalities...Need help.

Thanks for the help, I think I can do it now. By the other interval you mean when both expressions are negative, right?
Wed Aug 08, 2012 6:06 pm
Forum: Trigonometry
Topic: Solving Trig Inequalities...Need help.
Replies: 2
Views: 7492

### Solving Trig Inequalities...Need help.

Hello everyone, I looked everywhere online and nobody properly explains how to solve trig inequalities, and i'm still stuck. This is the problem... 2sin 2 x > sinx , 0 < x < 2pi I got to this point... sinx(2sinx - 1) > 0 I then split the two expressions and solved, which gave me solutions of 0, pi, ...