- Fri Nov 23, 2012 3:43 pm
- Forum: Beginning Algebra
- Topic: Where does this negative sign come from?
- Replies:
**4** - Views:
**3889**

I can think of no particular reason, other than the author's preference. It might be wise to consult with your instructor regarding preferred preference with respect to formatting. It's many years since I left school, I am using some old books written in the 1890s (which I found on the internet, no...

- Thu Nov 22, 2012 10:43 am
- Forum: Beginning Algebra
- Topic: Where does this negative sign come from?
- Replies:
**4** - Views:
**3889**

It might prove helpful to put the terms in descending order before doing the simplification: Ha, of course! I believe that's why 'Doh!' was invented! :lol: :oops: Note: If the negation sign is, as you have posted, in front of the entire expression, then the sign between the two terms in the numerat...

- Wed Nov 21, 2012 7:07 pm
- Forum: Beginning Algebra
- Topic: Where does this negative sign come from?
- Replies:
**4** - Views:
**3889**

Change to equivalent fraction: 1-\frac{2a^2+3}{a^2-2a+3} these are the steps I take: 1. multiply the whole number by the denominator 1(a^2-2a+3) which just gives me a^2-2a+3 2. add this to the numerator part a^2-2a+3-(2a^2+3) 3. which gives me a^2-2a+3-2a^2-3 4. and put this over the denominator to ...

- Tue Oct 30, 2012 7:18 pm
- Forum: Beginning Algebra
- Topic: What rule do I break here?
- Replies:
**2** - Views:
**2493**

Thank you for the explanation . When someone shows me something I'm stuck on, it always seems so easy! I need to slow down a bit and get more practice!

- Mon Oct 29, 2012 10:07 pm
- Forum: Beginning Algebra
- Topic: What rule do I break here?
- Replies:
**2** - Views:
**2493**

I'm factoring the difference of two cubes: mx 3 +my 3 -x-y, I get this far m(x+y)(x 2 +xy+y 2 )-x-y and then I do this m(x+y)(x 2 +xy+y 2 )-1(x+y) to get (m-1)(x+y)(x 2 +xy+y 2 ) which is wrong. I've worked out what I should have done (I think!), (x+y)m(x 2 +xy+y 2 )-x-y (x+y)(mx 2 +mxy+my 2 )-x-y (...

- Thu Oct 25, 2012 7:30 am
- Forum: Beginning Algebra
- Topic: Factor a^2-x^2-a-x
- Replies:
**2** - Views:
**2744**

Ah, yes! Now I can see. I looked at that for so long, but for some reason it just wouldn't form in my head! Thanks very much.

- Wed Oct 24, 2012 9:17 pm
- Forum: Beginning Algebra
- Topic: Factor a^2-x^2-a-x
- Replies:
**2** - Views:
**2744**

Hi, I have a problem: Factor a^2-x^2-a-x

I know what the answer is, but I don't understand how to get there...

I get as far as taking out the difference of two squares

(a+x)(a-x)-a-x

and now I'm lost as how to continue to get the answer which is (a+x)(a-x+1) it looks simple, but I'm baffled!

I know what the answer is, but I don't understand how to get there...

I get as far as taking out the difference of two squares

(a+x)(a-x)-a-x

and now I'm lost as how to continue to get the answer which is (a+x)(a-x+1) it looks simple, but I'm baffled!

- Mon Aug 06, 2012 5:15 pm
- Forum: Beginning Algebra
- Topic: Polynomial long division
- Replies:
**2** - Views:
**2198**

Ah, thank you for that! I suspected it may be something like that, but it seemed so complicated, I was sure I was overlooking something simple. I will give it a go and see if I can get it right! Well the question in the book was find the remainder, which they gave as 2x^4, mine is below and try as I...

- Sat Aug 04, 2012 3:13 pm
- Forum: Beginning Algebra
- Topic: Polynomial long division
- Replies:
**2** - Views:
**2198**

Hi, I have this long division exercise and I am completely stumped. This is the last in a set of 26, the others I have done without a problem, but I can't see how to start this one. Where I am stuck is in trying to divide the lead term 17x^4 by -5x^2 , which doesn't go exactly, so I end up with a fr...