Here's the equation you need to convert from Fahrenheit to Celsius:

C * (9/5) + 32 = F

Plug in 101.8 for F, and solve for C:

C * (9/5) + 32 = 101.8

- Wed Apr 18, 2012 12:09 am
- Forum: Pre-Algebra
- Topic: Temperature Conversion
- Replies:
**2** - Views:
**3586**

Here's the equation you need to convert from Fahrenheit to Celsius:

C * (9/5) + 32 = F

Plug in 101.8 for F, and solve for C:

C * (9/5) + 32 = 101.8

C * (9/5) + 32 = F

Plug in 101.8 for F, and solve for C:

C * (9/5) + 32 = 101.8

- Wed Apr 18, 2012 12:03 am
- Forum: Trigonometry
- Topic: meaning of symbols
- Replies:
**2** - Views:
**1698**

I'm not sure if you typed what you wanted to type or not.

But what you typed means that x is greater than or equal to 0 and less than or equal to 1. (Which simply means x is between 0 and 1.)

But what you typed means that x is greater than or equal to 0 and less than or equal to 1. (Which simply means x is between 0 and 1.)

- Wed Apr 18, 2012 12:00 am
- Forum: Calculus
- Topic: Differential Equations with 1/x
- Replies:
**1** - Views:
**1689**

Say you have a differential equation like this: (1/y)dy = dx When you integrate both sides, you get this: ln|y| = x + C Taking e to the both sides... |y| = e^(x + C) From here, my teacher says that the answer would simply be y = e^(x + C). However, taking a simpler situation involving absolute value...