Solved:

(original left hand side equation all divided by tan)

=

- Wed Feb 29, 2012 5:36 pm
- Forum: Trigonometry
- Topic: Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(x)-cot(
- Replies:
**4** - Views:
**4090**

Solved:

(original left hand side equation all divided by tan)

=

(original left hand side equation all divided by tan)

=

- Wed Feb 29, 2012 2:48 am
- Forum: Trigonometry
- Topic: Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(x)-cot(
- Replies:
**4** - Views:
**4090**

Well, I attempted the problem using your suggestion and I was able to reduce it to this, but do not see any further simplification possibilities: http://img339.imageshack.us/img339/1599/identity.gif The denominator could be changed to -cos(2x), but I don't see that helping. The denominator could be ...

- Sun Feb 26, 2012 6:14 am
- Forum: Trigonometry
- Topic: Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(x)-cot(
- Replies:
**4** - Views:
**4090**

Establish the following identity: \frac{\tan(x)}{\tan^2(x)\, -\, 1}\, =\, \frac{1}{\tan(x)\, -\, \cot(x)} Please help, I'm not sure if I'm starting this correctly. My attempt was(using "Left Hand Side"): · Convert the tan and tan^2 to sin(x)/cos(x) and sin^2(x)/cos^2(x) respectively. \mbox{Step 1. }...