Establish the following identity: \frac{\tan(x)}{\tan^2(x)\, -\, 1}\, =\, \frac{1}{\tan(x)\, -\, \cot(x)} Please help, I'm not sure if I'm starting this correctly. My attempt was(using "Left Hand Side"): · Convert the tan and tan^2 to sin(x)/cos(x) and sin^2...