thanks so much. my teacher used x+5 as equal to c in a quad form once.

but she sent out an email saying that she meant 5/x+4 as the original problem!

phew that makes it easier!

thanks for your help!

- Fri Oct 21, 2011 8:11 pm
- Forum: Intermediate Algebra
- Topic: Stuck while Solving a Rational Equation
- Replies:
**2** - Views:
**1780**

thanks so much. my teacher used x+5 as equal to c in a quad form once.

but she sent out an email saying that she meant 5/x+4 as the original problem!

phew that makes it easier!

thanks for your help!

but she sent out an email saying that she meant 5/x+4 as the original problem!

phew that makes it easier!

thanks for your help!

- Tue Oct 18, 2011 8:45 pm
- Forum: Intermediate Algebra
- Topic: Stuck while Solving a Rational Equation
- Replies:
**2** - Views:
**1780**

so here is the original problem; Solve. Use a solution set or interval notation where appropriate. 2x/(x-2) + 5/(x-4) = 13/(x^2+2x-8) this is what i've gotten so far. 2x(x-4)(x+4)+5(x-2)(x+4)-13(x-4)=0 2x(x^2-16)+5(x^2+2x-8)-13x+52=0 2x^3-32x+5x^2+10x-40-13x+52=0 2x^3+5x^2-35x+12=0 and im stuck. i c...