- Thu Oct 06, 2011 12:37 pm
- Forum: Beginning Algebra
- Topic: Literal equations that can't be solved?
- Replies:
**6** - Views:
**4037**

Awesome! Thanks for the help.

- Wed Oct 05, 2011 11:26 pm
- Forum: Beginning Algebra
- Topic: Literal equations that can't be solved?
- Replies:
**6** - Views:
**4037**

So if I understand that correctly, it would look something like:

-(b+c)/(1-xb) = a

Right? Thanks for the hints,BTW.

-(b+c)/(1-xb) = a

Right? Thanks for the hints,BTW.

- Wed Oct 05, 2011 8:50 pm
- Forum: Beginning Algebra
- Topic: Literal equations that can't be solved?
- Replies:
**6** - Views:
**4037**

I looked at that and maybe I'm missing a step.

By cross-multiply, I assume that you mean

x= (a+b+c)/ab

xab = a+b+c

Then if I subtract b & c from both sides I get

xab - b - c = a

My problem is that I do not know how to get the a out of the xab.

By cross-multiply, I assume that you mean

x= (a+b+c)/ab

xab = a+b+c

Then if I subtract b & c from both sides I get

xab - b - c = a

My problem is that I do not know how to get the a out of the xab.

- Wed Oct 05, 2011 1:48 am
- Forum: Beginning Algebra
- Topic: Literal equations that can't be solved?
- Replies:
**6** - Views:
**4037**

I have a literal equation that I am supposed to solve for 'a' but I think it is an equation that can't be rewritten. Can someone confirm this for me?

x=(a+b+c)/ab solve for a

I say it can't be solved. Am I wrong?

Thanks

x=(a+b+c)/ab solve for a

I say it can't be solved. Am I wrong?

Thanks