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Boolean expression simplification  TOPIC_SOLVED

Hello, I am trying to simplify this expression AC' + AB' + A'BC' + A'B'C TO AC' + BC' + B'C This is what I have done so far: AC' + A'BC' + AB' + A'B'C = C'(A+A'B) + B'(A+A'C) = C'(A+B) + B'(A+C) = AC' + BC' + AB' + BC' I wanna get rid off AB' but am not sure how?? Any helo will be appreciated.
by imu_1
on Wed Sep 07, 2011 3:00 pm
 
Forum: Discrete Math
Topic: Boolean expression simplification
Replies: 2
Views: 2579

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