- Wed Aug 24, 2011 9:03 am
- Forum: Beginning Algebra
- Topic: rectangle problem
- Replies:
**3** - Views:
**1892**

Here's the problem: The perimeter of a rectangle is 56 ft. The diagonal is 20 ft. Find the dimensions. I made this formula: 2(x + y) = 56 x squared + y squared = 400 (20 squared) but I don't know what to do from there. well first of all divide 56 by two to get 28. now you have o find the two numers...