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by akihironihongo
Wed Aug 24, 2011 9:03 am
Forum: Beginning Algebra
Topic: rectangle problem
Replies: 3
Views: 2003

Re: rectangle problem

Here's the problem: The perimeter of a rectangle is 56 ft. The diagonal is 20 ft. Find the dimensions. I made this formula: 2(x + y) = 56 x squared + y squared = 400 (20 squared) but I don't know what to do from there. well first of all divide 56 by two to get 28. now you have o find the two numers...

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