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How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0  TOPIC_SOLVED

Hi, Im trying to learn algebra on the side as I am in the army so I have no tutor or teacher to help, and Im have no idea how to solve this next equation. Hope you can Help. Its question "b)" http://img687.imageshack.us/img687/3293/img1605gy.jpg This isnt my homework or anything that Im tr...
by MathDrudge
on Sun Jul 24, 2011 10:33 am
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re:  TOPIC_SOLVED

stapel_eliz wrote:Is the equation as follows?



Thank you. :wink:


Yes it is :)
by MathDrudge
on Sun Jul 24, 2011 11:18 am
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re: Re:  TOPIC_SOLVED

Im trying to learn algebra on the side...and Im have no idea how to solve this next equation.... IS the --v-1 a mixed number (the second division from the left)? No; mixed numbers are whole numbers together with fractions, like "three and a half". They do not contain variables. Ok, so its...
by MathDrudge
on Mon Jul 25, 2011 6:51 am
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re: How to solve this problem  TOPIC_SOLVED

@stapel_eliz this is all the stages Im trying to solve the equation. Can you help? v\, -\, v\frac{v\, -\, 1}{4}\, +\, \frac{v^2\, -\, 5}{5}\, +\, \frac{1}{20}v^2\, =\, 0 20v\, -\, 20v\, 20(\frac{v\, -\, 1}{4}\), +\, 20(\frac{v^2\, -\, 5}{5}\), +\, 20(\frac{1}{20}v^2\), =\, 20...
by MathDrudge
on Mon Jul 25, 2011 2:29 pm
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re: How to solve this problem  TOPIC_SOLVED

What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either?
by MathDrudge
on Mon Jul 25, 2011 6:35 pm
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re:  TOPIC_SOLVED

What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either? There are still no mixed numbers in this equation. To learn what "terms" are, please try this lesson . To learn how to simplify v(v - 1), please try this lesson or this lesson . :wink: is ...
by MathDrudge
on Tue Jul 26, 2011 2:05 pm
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re: How to solve this problem  TOPIC_SOLVED

i still dont know what to do with this

by MathDrudge
on Thu Jul 28, 2011 4:17 pm
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re:  TOPIC_SOLVED

stapel_eliz wrote:
MathDrudge wrote:i still dont know what to do with this


Multiply it out. Cancel the four with the twenty. :wink:


by MathDrudge
on Fri Jul 29, 2011 9:23 am
 
Forum: Beginning Algebra
Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
Replies: 15
Views: 7769

Re: Solve, by steps  TOPIC_SOLVED

(\frac{1}{sqrt5}\, +\, \frac{1}{sqrt2}\,) :\, (\sqrt{5}\, +\, \sqrt{2}) (\frac{sqrt{2}\, +\, sqrt{5}}{sqrt10}\,) :\, (\sqrt{5}\, +\, \sqrt{2}) (\frac{sqrt{2}\, +\, sqrt{5}}{sqrt10}\,) :\, (\frac{\sqrt{5}\, +\, \sqrt{2}}{1}) \frac{sqrt{2}\, +\, sqrt{5}...
by MathDrudge
on Fri Aug 19, 2011 10:28 am
 
Forum: Pre-Algebra
Topic: Solve, by steps: (1/sqrt[5]+1/sqrt[2]):(sqrt[5]+sqrt[2])
Replies: 4
Views: 4275
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