- Fri Aug 19, 2011 11:06 am
- Forum: Pre-Algebra
- Topic: Solve, by steps: (1/sqrt[5]+1/sqrt[2]):(sqrt[5]+sqrt[2])
- Replies:
**4** - Views:
**7849**

That is all of the problem, I meant simplify in that case. yes it is division

- Fri Aug 19, 2011 10:28 am
- Forum: Pre-Algebra
- Topic: Solve, by steps: (1/sqrt[5]+1/sqrt[2]):(sqrt[5]+sqrt[2])
- Replies:
**4** - Views:
**7849**

(\frac{1}{sqrt5}\, +\, \frac{1}{sqrt2}\,) :\, (\sqrt{5}\, +\, \sqrt{2}) (\frac{sqrt{2}\, +\, sqrt{5}}{sqrt10}\,) :\, (\sqrt{5}\, +\, \sqrt{2}) (\frac{sqrt{2}\, +\, sqrt{5}}{sqrt10}\,) :\, (\frac{\sqrt{5}\, +\, \sqrt{2}}{1}) \frac{sqrt{2}\, +\, sqrt{5}}{sqrt10}\, *\, \frac{1}{\sqrt{5}\, +\, \sqrt{2}...

- Fri Aug 19, 2011 9:42 am
- Forum: Pre-Algebra
- Topic: Solve, by steps: (1/sqrt[5]+1/sqrt[2]):(sqrt[5]+sqrt[2])
- Replies:
**4** - Views:
**7849**

- Fri Jul 29, 2011 9:23 am
- Forum: Beginning Algebra
- Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
- Replies:
**15** - Views:
**11449**

Multiply it out. Cancel the four with the twenty.i still dont know what to do with this

- Thu Jul 28, 2011 4:17 pm
- Forum: Beginning Algebra
- Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
- Replies:
**15** - Views:
**11449**

i still dont know what to do with this

- Tue Jul 26, 2011 2:05 pm
- Forum: Beginning Algebra
- Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
- Replies:
**15** - Views:
**11449**

What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either? There are still no mixed numbers in this equation. To learn what "terms" are, please try this lesson . To learn how to simplify v(v - 1), please try this lesson or this lesson . :wink: is the soluti...

- Mon Jul 25, 2011 6:35 pm
- Forum: Beginning Algebra
- Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
- Replies:
**15** - Views:
**11449**

What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either?

- Mon Jul 25, 2011 2:29 pm
- Forum: Beginning Algebra
- Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
- Replies:
**15** - Views:
**11449**

@stapel_eliz this is all the stages Im trying to solve the equation. Can you help? v\, -\, v\frac{v\, -\, 1}{4}\, +\, \frac{v^2\, -\, 5}{5}\, +\, \frac{1}{20}v^2\, =\, 0 20v\, -\, 20v\, 20(\frac{v\, -\, 1}{4}\), +\, 20(\frac{v^2\, -\, 5}{5}\), +\, 20(\frac{1}{20}v^2\), =\, 20*0 20v\, -\, 20v\frac{20...

- Mon Jul 25, 2011 6:51 am
- Forum: Beginning Algebra
- Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
- Replies:
**15** - Views:
**11449**

Im trying to learn algebra on the side...and Im have no idea how to solve this next equation.... IS the --v-1 a mixed number (the second division from the left)? No; mixed numbers are whole numbers together with fractions, like "three and a half". They do not contain variables. Ok, so its multiplie...

- Sun Jul 24, 2011 11:18 am
- Forum: Beginning Algebra
- Topic: How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0
- Replies:
**15** - Views:
**11449**

Yes it isIs the equation as follows?

Thank you.