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Hi, Im trying to learn algebra on the side as I am in the army so I have no tutor or teacher to help, and Im have no idea how to solve this next equation. Hope you can Help. Its question "b)" http://img687.imageshack.us/img687/3293/img1605gy.jpg This isnt my homework or anything that Im tr...

stapel_eliz wrote:Is the equation as follows?



Thank you.

Yes it is

Im trying to learn algebra on the side...and Im have no idea how to solve this next equation.... IS the --v-1 a mixed number (the second division from the left)? No; mixed numbers are whole numbers together with fractions, like "three and a half". They do not contain variables. Ok, so its...

@stapel_eliz this is all the stages Im trying to solve the equation. Can you help? v\, -\, v\frac{v\, -\, 1}{4}\, +\, \frac{v^2\, -\, 5}{5}\, +\, \frac{1}{20}v^2\, =\, 0 20v\, -\, 20v\, 20(\frac{v\, -\, 1}{4}\), +\, 20(\frac{v^2\, -\, 5}{5}\), +\, 20(\frac{1}{20}v^2\), =\, 20...

What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either?

What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either? There are still no mixed numbers in this equation. To learn what "terms" are, please try this lesson . To learn how to simplify v(v - 1), please try this lesson or this lesson . :wink: is ...

i still dont know what to do with this

(\frac{1}{sqrt5}\, +\, \frac{1}{sqrt2}\,) :\, (\sqrt{5}\, +\, \sqrt{2}) (\frac{sqrt{2}\, +\, sqrt{5}}{sqrt10}\,) :\, (\sqrt{5}\, +\, \sqrt{2}) (\frac{sqrt{2}\, +\, sqrt{5}}{sqrt10}\,) :\, (\frac{\sqrt{5}\, +\, \sqrt{2}}{1}) \frac{sqrt{2}\, +\, sqrt{5}...