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Factoring 40x^3 - 5  TOPIC_SOLVED

Hello, I'am having problems with factoring 40X^3 - 5 can anyone show me how to do this?
by Luke53
on Sun Mar 13, 2011 10:00 am
 
Forum: Beginning Algebra
Topic: Factoring 40x^3 - 5
Replies: 2
Views: 1442

Re: Factoring  TOPIC_SOLVED

OK, thanks for the relply, I know thanks to the Wikipedia factoring page you send me, how to solve this problem now. I divide each term by 5 to get 8x^3 - 1 that turns in to (2x)^3 - 1^3, then 2x - 1 is a factor, the other factor is found by long division of (2x^3 - 1)/ (2x - 1) = 4x^2 + 2x + 1. I n...
by Luke53
on Sun Mar 13, 2011 8:23 pm
 
Forum: Beginning Algebra
Topic: Factoring 40x^3 - 5
Replies: 2
Views: 1442

system of linear equations  TOPIC_SOLVED

Is there an easy way to solve a system like this one?
x y/(3x-4y)=2/11
y z/(2y+3z)=6/5
x z/(x-z)=3/2
Luke
by Luke53
on Thu Apr 07, 2011 7:57 am
 
Forum: Beginning Algebra
Topic: system of linear equations
Replies: 10
Views: 3536

Word problem: A train is travelling from A to B.  TOPIC_SOLVED

Can't solve this one, so please help. A train is travelling from A to B. After it travelled for one hour, it stops for one hour and then continues it's voyage with a speed that is equal of 3/5 of the initial speed. It arrives at B with a delay of 3 hours . If the train would have stopped 50 km furth...
by Luke53
on Thu Apr 07, 2011 8:22 am
 
Forum: Beginning Algebra
Topic: Word problem: A train is travelling from A to B.
Replies: 3
Views: 1414

Re: system of linear equations  TOPIC_SOLVED

Giving another example, of how it should be done according to my textbook: given the following system: x y/(x+y)=8/3 y z/(y+z)=8/5 x z/(x+z)=4/3 the first eqn is the same as: (1/x)+(1/y)=3/8 (1) the second eqn is: (1/y)+(1/z)=5/8 (2) the third eqn: (1/x)+(1/z)=6/8 (3) So the sum of the three last eq...
by Luke53
on Thu Apr 07, 2011 4:48 pm
 
Forum: Beginning Algebra
Topic: system of linear equations
Replies: 10
Views: 3536

Re: How to solve a stated problem  TOPIC_SOLVED

x^2+7x-144=0
x=9 or x=-16
x=9, since a rectangle has no negative lenght.
9*16=144
by Luke53
on Thu Apr 07, 2011 7:41 pm
 
Forum: Beginning Algebra
Topic: How to solve a stated problem
Replies: 1
Views: 1009

Re: system of linear equations  TOPIC_SOLVED

Is there an easy way to solve a system like this one? x y/(3x-4y)=2/11 y z/(2y+3z)=6/5 x z/(x-z)=3/2 Luke Can one transform the three equations into the 1/x + 1/y form like in the previous example? Applying the tranformation to the third eqn: x z/(x-z) = 3/2, would be something like: (1/z) - (1/x) =...
by Luke53
on Fri Apr 08, 2011 8:32 am
 
Forum: Beginning Algebra
Topic: system of linear equations
Replies: 10
Views: 3536

Re: Word problem: A train is travelling from A to B.  TOPIC_SOLVED

distance(ab) = d(ab); v = initial speed; t = normal time of arrival. d(ab) = v * t first case: d(ab) = v *1 + 3/5 *v *(t+3 -1) d(ab) = v + 3/5 v * (t+2) d(ab) = v + 3/5 * v *t + 6/5 * v second case: d(ab) = v + 50 + 3/5 *v * (t +3 -1 - 1.66) d(ab)= v + 50 +3/5 v *t + 1/5 * v since the distance is th...
by Luke53
on Fri Apr 08, 2011 2:52 pm
 
Forum: Beginning Algebra
Topic: Word problem: A train is travelling from A to B.
Replies: 3
Views: 1414

Re: system of linear equations  TOPIC_SOLVED

I don't know how to do this so please help.
Luke.
by Luke53
on Fri Apr 08, 2011 3:03 pm
 
Forum: Beginning Algebra
Topic: system of linear equations
Replies: 10
Views: 3536

Re: system of linear equations  TOPIC_SOLVED

I know that : x y /(x+y) = 8/3 is the same as 1/x + 1/y = 3/8
Could this sort of transformation also be done with: x y / (3x - 4y) = 2/11 ? ( guess not, but I'm not sure).
Thanks.
by Luke53
on Sat Apr 09, 2011 1:34 pm
 
Forum: Beginning Algebra
Topic: system of linear equations
Replies: 10
Views: 3536
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