- Sun Feb 27, 2011 10:57 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Rewriting a logarithmic function
- Replies:
**3** - Views:
**2124**

Ah, I should start with adding the 5.1 then?

- Sun Feb 27, 2011 10:51 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Properties of logarithmic functions
- Replies:
**5** - Views:
**2904**

Well if log_{b}(5)=.9 and log_{b}b=1 then .9(1)=.9

- Sun Feb 27, 2011 10:28 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Rewriting a logarithmic function
- Replies:
**3** - Views:
**2124**

If I had the function R=2.3log(A+3000)-5.1 and I wanted solve for A in terms of R, would A=10^{((R/2.3)-5.1))}-3000 be correct?

- Sun Feb 27, 2011 10:18 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Properties of logarithmic functions
- Replies:
**5** - Views:
**2904**

.9

Awesome, thank you.

Awesome, thank you.

- Sun Feb 27, 2011 9:32 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Properties of logarithmic functions
- Replies:
**5** - Views:
**2904**

I have a series of problems that state: given that log b (2)=.39, log b (3)=.61 and log b (5)=.9, find the following for logs, do no try to find "b" Then there are easy ones to solve using multiplication and division properties, but there is one I'm not sure about. b log b (5) Can that go any furthe...