- Sun Feb 27, 2011 12:59 am
- Forum: Beginning Algebra
- Topic: Equation Of A Straight line?
- Replies:
**1** - Views:
**898**

Sorry about my last post, i put the working out for a differnt question and i dont know how to delete the question. This is the real working out.. Find the equation of the following straight line through (0,-1) and ( 2, -9) -9-1 / 2-0 = -10/2 y=10/2x + c x = 0 y = -1 -1 = -10/2 (0) + c giving c = -1...

- Sat Feb 26, 2011 11:16 am
- Forum: Beginning Algebra
- Topic: Equations Of Straight Lines - What Am I Doing Wrong?
- Replies:
**1** - Views:
**1805**

find the eqaution of the straight line with the gradient 0.5 and passing through the point (3, 4)

m = 0.5

x = -1

y = 10

y=mx+b

(-10) = (0.5)(-1) + b

-10 = -0.5 + b

b = -9.5

therefore my answer would be y = 0.5x - 9.5

but the answer is y = -4x-1

m = 0.5

x = -1

y = 10

y=mx+b

(-10) = (0.5)(-1) + b

-10 = -0.5 + b

b = -9.5

therefore my answer would be y = 0.5x - 9.5

but the answer is y = -4x-1