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find the eqaution of the straight line with the gradient 0.5 and passing through the point (3, 4)

m = 0.5
x = -1
y = 10

y=mx+b
(-10) = (0.5)(-1) + b
-10 = -0.5 + b
b = -9.5

therefore my answer would be y = 0.5x - 9.5
but the answer is y = -4x-1

Sorry about my last post, i put the working out for a differnt question and i dont know how to delete the question. This is the real working out.. Find the equation of the following straight line through (0,-1) and ( 2, -9) -9-1 / 2-0 = -10/2 y=10/2x + c x = 0 y = -1 -1 = -10/2 (0) + c giving c = -1...