- Wed Feb 02, 2011 5:15 am
- Forum: Calculus
- Topic: Area of curves in the first quadrant
- Replies:
**2** - Views:
**3699**

Thanks! I actually got the problem right. Thanks for the link and explanation!

- Wed Feb 02, 2011 5:14 am
- Forum: Calculus
- Topic: Couple of Questions Regarding Integration and Checking Work
- Replies:
**3** - Views:
**1887**

Ok, for question 1... I am given a initial value problem dy/dx = 11sqrt(y)cos(sqrt(y))^2 for x>0 and y(0) = (pi^2)/16 - First I isolated dy and dx respectively ending with... - (11sqrt(y)cos(sqrt(y))^2)dy = dx So far so good? Am I approaching this problem right? - Now, I want to integrate both sides...

- Fri Jan 28, 2011 5:01 am
- Forum: Calculus
- Topic: Area of curves in the first quadrant
- Replies:
**2** - Views:
**3699**

I am having problems with this question. I'm not sure how to start and approach this question. Find the area of the region in the first quadrant that is bounded above by the curve y = e^(3x), below by the curve y = e^x, and on the right by the line x = ln(5). I know I have to integrate e^x to find t...